SOLUTION: find amplitude and period of the function y=1+.5 cos πx
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Question 595030: find amplitude and period of the function y=1+.5 cos πx
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find amplitude and period of the function y=1+.5 cos πx
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Equation for the sin function: y=Acos(Bx+C), A=amplitude, period=2π/B, phase shift=C/B
For given equation: y=1+.5cosπx
B=π
Phase shift: none
period=2π/B=2π/π=2 (radians)
1/4 period=1/2
..
coordinates of basic equation for on period: (0,.5), (.5,0), (1,-.5), (1.5,0), (2,.5)
Amplitude:
maximum=.5
minimum=-.5
..
The 1 in the equation bumps the basic curve up one unit.
coordinates of final configuration for on period: (0,1.5), (.5,1), (1,.5), (1.5,1), (2,1.5)
Amplitude:
maximum=1.5
minimum=.5
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