SOLUTION: Determine the limit (as x approaches 0) of (cos3x-cos4x)/x^2.
I've tried using L'Hopital's but the denominator would still be undefined...
Thank you.
Algebra.Com
Question 590915: Determine the limit (as x approaches 0) of (cos3x-cos4x)/x^2.
I've tried using L'Hopital's but the denominator would still be undefined...
Thank you.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
L'Hôpital works for }{g(x)}\ =\ \lim_{x\rightarrow{a}}\,\frac{f^n(x)}{g^n(x)})
, so just take the second derivative of your numerator and denominator. The denominator will then be a constant and the limit trivial.
John
My calculator said it, I believe it, that settles it
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