SOLUTION: Solve the equation on the interval [0,2pi). sin(x)sec(x)=2 sin(x)

Question 590098: Solve the equation on the interval [0,2pi).
sin(x)sec(x)=2 sin(x)
Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!

          sin(x)sec(x) = 2sin(x)
sin(x)sec(x) - 2sin(x) = 0
    sin(x)[sec(x) - 2] = 0

sin(x) = 0;    sec(x) - 2 = 0

     x = 0,p       sec(x) = 2
                   cos(x) = 
                        x = , 

Edwin

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