SOLUTION: Find all values of x in interval [0, 2(pi)] that satisfy sin2(x)=cos(x). I am having a problem with this question. I am getting half of the values in the answer so I am missing

Question 587923: Find all values of x in interval [0, 2(pi)] that satisfy sin2(x)=cos(x).
I am having a problem with this question. I am getting half of the values in the answer so I am missing something. Any help would be great!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find all values of x in interval [0, 2(pi)] that satisfy
sin2(x)=cos(x).
1-cos^2x=cosx
cos^2x+cosx-1=0
Solve for cosx by quadratic formula:
a=1, b=1, c=-1
cosx=[-1�√(1-4*1*-1)]/2*1
cosx=(-1�√5)/2
cosx=(-1�2.236)/2
cosx=-1.618 (reject, cosx≥-1)
cosx=.618
x≈.905 and 5.378 radians in quadrants I and IV where cos>0
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