SOLUTION: Can you please exlpain step by step how to solve 2/x-3 - 4/x+3 = 8/x^2-9

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The third denominator is the difference of squares and can be factored to;
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Multiply each term by (x-3)(x+3)
(x-3)(x+3)* - (x-3)(x+3)* = (x-3)(x+3)*
Cancel the denominators and you have:
2(x+3) - 4(x-3) = 8
2x + 6 - 4x + 12 = 8
2x - 4x + 18 = 8
-2x = 8 - 18
-2x = -10
x = +5
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Check this in the original problem for x = 5
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