SOLUTION: 1)1. Solve the equation 3(2x-1) + x = 5x+3. a. 0 b. 3 c. 3/2 d. no solution 2)2. Use the quadratic formula to solve y2+10y+24 = 0. 3)3. Solve by factoring: a2 -5a-14 = 0. a.

Question 57442: 1)1. Solve the equation 3(2x-1) + x = 5x+3.
a. 0
b. 3
c. 3/2
d. no solution
2)2. Use the quadratic formula to solve y2+10y+24 = 0.
3)3. Solve by factoring: a2 -5a-14 = 0.
a. 5, 14
b. -7, 2
c. 2, 7
d. 7, -2
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
a. (- ∞ , 4]
b. [4, ∞ )
c. (- ∞ , 2/3]
d. [2/3, ∞ )

Found 2 solutions by funmath, Nate:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
1)1. Solve the equation 3(2x-1) + x = 5x+3.
. 0
b. 3
c. 3/2
d. no solution
3(2x-1)+x=5x+3
6x-3+x=5x+3
7x-3=5x+3
-5x+7x+3=-5x+5x+3
2x+3=3
2x+3-3=3-3
2x=0
2x/2=0/2
x=0 (a)
:
2)2. Use the quadratic formula to solve .
a=1, b=10,c=24
The quadratic formula is:

and
and
and
and
:
3)3. Solve by factoring: .
a. 5, 14
b. -7, 2
c. 2, 7
. 7, -2
Two numbers that multiply to get -14, but add to get -5 are -7 and 2. -7*2=-14 and -7+2=-5

and
and
:
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
a. (- infinity; , 4]
b. [4, infinity )
. (-infinity, 2/3]
d. [2/3, infinity )

(-infinity,2/3]
Happy Calculating!!!
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
1)1. Solve the equation 3(2x-1) + x = 5x + 3.
6x - 3 + x = 5x + 3
7x - 3 = 5x + 3
2x = 6
x = 3
b.
2)2. Use the quadratic formula to solve y2+10y+24 = 0.

and
3)3. Solve by factoring: a2 - 5a - 14 = 0.
(x - 7)(x + 2) = 0
x = 7 and x = -2
d.
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.

(-,2/3]
c.
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