SOLUTION: The range of sin^-1 is [-pi/2,pi/2], but the range of tan^-1 is (-pi/2,pi/2), Why don't we need the endpoints on the second case? That is, why doesn't arctangent ever take the valu

SOLUTION: The range of sin^-1 is [-pi/2,pi/2], but the range of tan^-1 is (-pi/2,pi/2), Why don't we need the endpoints on the second case? That is, why doesn't arctangent ever take the valu

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Question 572972: The range of sin^-1 is [-pi/2,pi/2], but the range of tan^-1 is (-pi/2,pi/2), Why don't we need the endpoints on the second case? That is, why doesn't arctangent ever take the values pi/2 or -pi/2?
explain your answer.
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Because tan(-pi/2) and tan(pi/2) are undefined (since tan x = sin x / cos x, cos (-pi/2) and cos (pi/2) are 0).
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