SOLUTION: I dont even know where to begin to start this problem
1+sin squared 40 degrees + sin squared 50 degrees
Algebra.Com
Question 572848: I dont even know where to begin to start this problem
1+sin squared 40 degrees + sin squared 50 degrees
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1+sin squared 40 degrees + sin squared 50 degrees
-----
sin(50) = cos(40)
--> 1 + sin^2(40) + cos^2(40)
= 1 + 1
= 2
RELATED QUESTIONS
This is a 3-part question.
1) Solve the following equation. Which of its values from... (answered by solver91311)
i dont even know where to start with this problem. -1 < (9-12x)/7 < 8
(answered by Alan3354)
The expression cos^2 40 degrees - sin^2 40 degrees has the same value as
(1) sin 20... (answered by jim_thompson5910)
I DONT KNOW HOW TO SOLVE THIS PROBLEM OR EVEN KNOW WHERE TO START..... (answered by jim_thompson5910)
Hello, i need help on solving this equation. I dont even know where to start.
t-2/t-1= (answered by ankor@dixie-net.com)
How to work this problem: tan 40 degrees - sin 40 degrees/cos 40 degrees.
I think the... (answered by sudhanshu_kmr)
don't know how to type exponent. the equation is x squared plus 0x minus 1 equals 0. i... (answered by Earlsdon)
cos squared 40 degrees minus cos squared 50... (answered by ikleyn)
Please help me solve this equation using half angle formula: sin 22 degrees 30'
I am... (answered by solver91311)