SOLUTION: How do I work this? I am drawing a blank. Thank You for any help.
sin θ = - ½ , 180° < 0 < 270°, find tan θ
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sin θ = - ½ , 180° < 0 < 270°, find tan θ
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Question 570166: How do I work this? I am drawing a blank. Thank You for any help.
sin θ = - ½ , 180° < 0 < 270°, find tan θ Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! sin θ = - ½ , 180° < 0 < 270°, find tan θ
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Theta is in the 3rd Quadrant where x and y are both negative.
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Since sin = y/r, y = -1 and r = 2
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solve for "x":
2^2 = (-1)^2 + x^2
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x = -sqrt(3) (negative because theta is in the 3rd quadrant)
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Then tan(theta) = y/x = -1/(-sqrt(3)) = 1/sqrt(3) = (1/3)sqrt(3)
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Cheers,
Stan H.
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