SOLUTION: find values of x for 6 sin^2(x) = 3 between [0,2pi]

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Question 561795: find values of x for 6 sin^2(x) = 3 between [0,2pi]
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
find values of x for 6 sin^2(x) = 3 between [0,2pi]
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6 sin^2(x) = 3
Divide by 6:
sin^2(x) = 1/2 -> sin^2(x) - 1/2 = 0
Factor:
%28sin%28x%29%2B1%2Fsqrt%282%29%29%28sin%28x%29-1%2Fsqrt%282%29%29+=+0
This gives sin%28x%29+=+1%2Fsqrt%282%29, -1%2Fsqrt%282%29
On the interval [0,2pi], the solutions are pi/4,3pi/4,5pi/4,7pi/4