# SOLUTION: when will lim [(ax^2 + bx + c)/ (x^2 - x -6)] = 1 x->0 a) a = 0 b) a = 1 c) b = -1 d) c = -6 im getting 2 different answers so Im a bit confused... Please can so

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: when will lim [(ax^2 + bx + c)/ (x^2 - x -6)] = 1 x->0 a) a = 0 b) a = 1 c) b = -1 d) c = -6 im getting 2 different answers so Im a bit confused... Please can so      Log On

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 Click here to see ALL problems on Trigonometry-basics Question 551693: when will lim [(ax^2 + bx + c)/ (x^2 - x -6)] = 1 x->0 a) a = 0 b) a = 1 c) b = -1 d) c = -6 im getting 2 different answers so Im a bit confused... Please can some one explain it to me with solution thanks...Answer by richard1234(5390)   (Show Source): You can put this solution on YOUR website!We can substitute directly because the function is continuous everywhere near 0 (the only "problems" are near -2 and 3), and obtain c = -6. We cannot claim any of the other choices, because they may or may not be true. Additionally, we cannot use L'Hopital's rule, because we need both limits to equal 0 or infinity.