SOLUTION: cos(arcsin(-3/5))
Algebra.Com
Question 545805: cos(arcsin(-3/5))
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
cos(arcsin(-3/5))
arcsin(-3/5) is a reference angle whose sin=-3/5 in quadrant IV where sin<0 and cos>0.
note: arcsin(-3/5) could also be in quadrant III where sin is also<0, but its domain is: [-π/2, π/2]
..
cos of this same reference angle=4/5
Therefore, cos(arcsin(-3/5))=4/5
RELATED QUESTIONS
Cos(arcsin(5/13)-arctan(3/4)) (answered by lwsshak3)
Evaluate cos(Arcsin (3/5) + Arctan... (answered by jsmallt9)
if c=arctan(3) + arcsin(5/13) find... (answered by Alan3354)
if C=arctan(3) + arcsin(5/13) find cos(C)
Without... (answered by Edwin McCravy,ikleyn)
Evaluate:
(a)
Arcsin (-1/2)
(b)
sin [ Arcsin... (answered by stanbon)
Evaluate without a calculator:
A) sin{ Arctan [(-5/13)]}
B)cos{ Arcsin[(-3/4)]}... (answered by stanbon)
cos [Arcsin (-1/4)... (answered by stanbon)
calculate the exact value of the following expressions justifying the steps of... (answered by stanbon)
What is the exact value of :
arcsin (-sqrt(3)/4)
cot(tan inverse 5)
cos inverse... (answered by stanbon)