SOLUTION: I need to find the amplitude, period, and phase shift. Then graph one period of the function. y=1/2sin(x+pi)

Question 543603: I need to find the amplitude, period, and phase shift. Then graph one period of the function. y=1/2sin(x+pi)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I need to find the amplitude, period, and phase shift. Then graph one period of the function. y=1/2sin(x+pi)
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Equation for graphing sin functions: y=Asin(Bx-C), A=amplitude, Period=2π9/B, Phase-shift (C/B)
For given function: y=1/2sin(x+pi)
Amplitude=1/2
B=1
period=2π/B=2π/1=2π
1/4 period=2π/4=π/2
Phase shift = C/B=π/1=π (shift to the left)
..
Graphing the function on a (x,y) coordinate system with the x-axis scaled in radians"
For one period:
Coordinates for basic sin function: (0,0), (π/2,1), (π,0), (3π/2,-1),(2π/0)
Multiply y-coordinates by (1/2) : (0,0), (π/2,1/2), (π,0), (3π/2,-1/2), (2π/0)
For the final configuration: shift x-coordinates π units to the left.
(-π,0), (-π/2,1/2), (0,0), (π/2,-1/2), (π,0)
you now have the coordinates with which to plot the graph for one period
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