SOLUTION: Solve the given equation 2 sin 2θ − 3 sin θ = 0
Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, write no
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Question 542083: Solve the given equation 2 sin 2θ − 3 sin θ = 0
Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, write no solution.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve the given equation
2 sin 2θ − 3 sin θ = 0
----
2(2sin*cos) - 3sin = 0
----
2sin(2cos-3) = 0
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2sin(x) = 0 or 2cos-3 = 0
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x = 0 or pi ; cos(x) = 3/2
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x = 0 or pi since cos(x) cannot be greater than 1:
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Cheers,
Stan H.
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