SOLUTION: how do i verify and prove that sin(beta - 3[pi]/2) = cos (beta)

Algebra.Com
Question 535135: how do i verify and prove that
sin(beta - 3[pi]/2) = cos (beta)

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
how do i verify and prove that
sin(beta - 3[pi]/2) = cos (beta)
**
Use x in place of beta
starting with left side
use addition formula for sin
sin(x-3π/2)=[sinx*cos(3π/2)]-[cosx*sin(3π/2)]
cos(3π/2)=0
sin(3π/2)=-1
sin(x-3π/2)=[sinx*0]-[cosx*(-1)]=0-(-cosx)=cosx
Verified:
left side=right side

RELATED QUESTIONS

If I have sec beta - cos beta = sin beta * tan beta how do I verify... (answered by lwsshak3)
Prove that sin(alpha+beta)= sin alpha cos beta+cos alpha sin beta I have no idea how... (answered by richard1234)
sin alpha = 3/5, pi/2 < alpha (answered by Fombitz)
Prove: sec(alpha + beta)=... (answered by lynnlo)
Find the Exact value (No Decimals) of sin(105 degrees) using the sum or difference... (answered by Theo)
3*cos(beta) + 3 =... (answered by ikleyn)
{{{3*cos(beta) + 3}}} =... (answered by ikleyn)
what is (1-sin^2 beta)/cos beta= cos... (answered by Alan3354)
Show that sin(alpha+beta)=sin alpha*cos beta +cos alpha*sin beta. I have no idea how... (answered by stanbon)