SOLUTION: Find all the solutions in the interval (0,2pi). square root of 2 times sinx secx = 2sinx

Question 533337: Find all the solutions in the interval (0,2pi).
square root of 2 times sinx secx = 2sinx
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find all the solutions in the interval (0,2pi).
square root of 2 times sinx secx = 2sinx
**
√2sinx secx=2sinx
√2sinx secx-2sinx=0
sinx(√2secx-2)=0
..
sinx=0
x=arcsin(0)=0 and π
..
√2secx-2=0
secx=2/√2=1/cosx
cosx=√2/2
x=arccos(√2/2)=π/4 and 7π/4 (in quadrants I and IV where cos and sec>0)
solutions: 0, π/4, π, and 7π/4
RELATED QUESTIONS
[(Sqrt2) secx-2](2sinx+1)=0 Find all solutions for this equation with the interval [0,... (answered by lwsshak3)

Calculating trigonometric equations for x in radians. Find all the solutions of the... (answered by greenestamps)

Find all solutions for 2sinx+2=0 on the interval [0, 2pi). I tried to factor it and got... (answered by jsmallt9)

1. Find all solutions of sinx= √3/2 in the interval [-2pi,... (answered by lwsshak3)

find all solutions: 3sin^2x+2sinx-1=0; in the interval... (answered by ikleyn)

find all solutions of equation in the interval [0, 2pi) 2 cos theta+square root 3 = 0 (answered by Fombitz)

Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 (answered by lwsshak3)

find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2... (answered by stanbon)

could you help me find all the solutions in the interval [0, 2pi)... (answered by lwsshak3)