SOLUTION: -2sin(t)+2cos(2t)=0

Question 532232: -2sin(t)+2cos(2t)=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
-2sin(t)+2cos(2t)=0
--------
-2sin(t) + 2*(cos^2 - sin^2) = 0
---
-2sin(t) +2(1-2sin^2) = 0
---
-2sin(t) + 2 - 4sin^2 = 0
---
4sin^2 + 2sin -2 = 0
---
2sin^2 + sin - 1 = 0
---
(2sin-1)(sin+1) = 0
----
2sin = 1 or sin = -1
----
sin = 1/2 or sin = -1
t = pi/6 or (5/6)pi or (3/2)pi
===================================
Cheers,
Stan H.
===============
RELATED QUESTIONS
Can�t we use the formula cox2x=2cos^2x-1 or 1-2sin^2x while solving... (answered by KMST)

Find the exact value of sin^-1(-sqrt3/2). a.2sin(4t)cos(2t) b.2cos(4t)sin(2t)... (answered by stanbon)

sketch a graph of: y=1-2t+2sin(Pi t)... (answered by Fombitz)

Solve. (2t^2+t)^2-4(2t^2+t)+3=0. Let n=(2t^2+t). (answered by stanbon)

Which expression is equivalent to cos(1.4x) − cos(0.6x)? a. -2sin x sin(0.4x) b.... (answered by math_tutor2020)

solve for t... (answered by nerdybill)

Which expression is equivalent to sin(0.6x)-sin(0.4x)? a. 2cos(0.5x)sin(0.1x) b.... (answered by MathLover1)

Find all solutions for (Let @ represent theta) (2sin@-1)(2cos@+3)=0 Thank you in... (answered by Alan3354)

Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)