SOLUTION: How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?

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 Question 530529: How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?Answer by stanbon(57407)   (Show Source): You can put this solution on YOUR website!How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x? ------------------------------- (4x+3)/(20x^2+23x+6) --- Factor: (4x+3)/[(4x+3)(5x+2)] Restrictions on "x": x cannot be -3/4; x cannot be -2/5. ---- Cancel the factor common to numerator and denominator to get: = 1/(5x+2) Cheers, Stan H. =========