SOLUTION: How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?

Question 530529: How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?
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(4x+3)/(20x^2+23x+6)
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Factor:
(4x+3)/[(4x+3)(5x+2)]
Restrictions on "x":
x cannot be -3/4; x cannot be -2/5.
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Cancel the factor common to numerator and denominator to get:
= 1/(5x+2)
Cheers,
Stan H.
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