SOLUTION: Solve the equation on the interval 0 < theta < 2pi
cos^2 theta-sin^2 theta+sin theta=0
Algebra.Com
Question 525248: Solve the equation on the interval 0 < theta < 2pi
cos^2 theta-sin^2 theta+sin theta=0
Answer by tarungehlot(9) (Show Source): You can put this solution on YOUR website!
let theta = @
cos ^2 @ - sin ^2 @ + sin @=0
now
cos ^2 @ = 1- 2sin ^2 @
1 - sin ^2 @ - sin ^2 @ + sin @=0
-2 sin ^2 @ +sin @ +1=0
(2sin @ -1)(sin @ +1)=0
hence
@= pie/6( in first and second quadrant ) and @ = - pie /2 ( in 3 and 4 quadrant)
RELATED QUESTIONS
Solve the equation sin(theta)+cos(theta)= 2(sin(theta)- cos(theta)), for 0 (answered by lwsshak3,KMST)
Using the identity
tan theta = Sin theta/Cos theta
Solve 2 sin theta + cos theta =... (answered by lwsshak3)
Solve the equation on the interval of 0 < theta <2pi
sqrt 3 sin theta+cos... (answered by solver91311)
Solve for theta on the interval 0 <= theta <= 2pi.
2sin(theta)cos(theta) - cos(theta)... (answered by Fombitz)
A)write the equation cos(2 theta)-sin(theta)=0 in terms of sin (theta)
B) Hence solve... (answered by stanbon)
Solve each equation on the interval 0 (answered by lwsshak3)
what is the answer to this problem? sin theta +cos theta/2=0 on the interval [0,... (answered by Alan3354)
use a calculator to solve the equation on the interval 0<=theta<2pi... (answered by Alan3354)
Find all radian values of theta in the interval 0 (answered by Fombitz)