SOLUTION: tan(sin^-1(3/5))

Algebra.Com
Question 523394: tan(sin^-1(3/5))
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
tan(sin^-1(3/5))
**
You are working with a right triangle whose sin=3/5=opposite side/hypotenuse. The adjacent side, by Pythagorean Theorem=4
So tan of the angle=opposite side/adjacent side=3/4

RELATED QUESTIONS

Tan(sin^-1... (answered by stanbon)
tan[sin^-1(-3/5)+cos^-1(1/2)] (answered by lwsshak3)
Tan(sin^-1(-3/8) (answered by ikleyn)
find the exact value of each expression. 35) sec(inverse sin 5/13 minus inverse tan... (answered by lwsshak3)
evaluate the following 1. tan inverse [tan 3pie/4] 2. sin(cos inverse 3/5) 3.... (answered by stanbon)
Evaluate: 1. tan [(Arcsec -10)/2] 2. tan [Arctan2 - Arccos 3/5] 3. 4cos^2(x/2) =... (answered by lwsshak3)
Find the exact value of the expression sin((tan^-1 3/4) +(cos^-1... (answered by lwsshak3)
tan... (answered by ikleyn)
Sin=3/5 Cot=1 Sec=7/2 Cos=9/40 Tan=√3... (answered by ikleyn)