SOLUTION: solve equation, where 0(degrees)<= X <= 360(degrees). Round approximate answers to the nearest tenth of a degree. 3-5sin(x)=4sin(x)+1 show process of solving the equation, I

Question 522180: solve equation, where 0(degrees)<= X <= 360(degrees). Round approximate answers to the nearest tenth of a degree.
3-5sin(x)=4sin(x)+1
show process of solving the equation, I alrady have the answers but do not understand how they were reached.
answers: 12.8(degrees), 167.2(degrees)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve equation, where 0(degrees)<= X <= 360(degrees). Round approximate answers to the nearest tenth of a degree.
3-5sin(x)=4sin(x)+1
9sinx=2
sinx=2/9
arcsin(2/9)=12.8� and 167.2� in quadrants I and II where sin>0
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