SOLUTION: Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first. cos^2 x- sin^2 x = sqr3/2

Question 519106: Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.
cos^2 x- sin^2 x = sqr3/2
**
cos^2x-sin^2x=√3/2
1-sin^2x-sin^2x=√3/2
1-sin^2x-(1-cos^2x)=√3/2
1-sin^2x-1+cos^2x=√3/2
cos^2x-sin^2x=√3/2
cos(2x)=√3/2
2x=π/6
x=π/12
RELATED QUESTIONS
Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal (answered by jsmallt9)

solution set for cos(theta/2)=1/2 where theta is greater than or equal to 0 and less than (answered by MathLover1)

Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)

2sinx-sqrt(2)tanx=0 Solve for angles greater than or equal to zero and less than 2pi. (answered by lwsshak3)

please solve the equation (x is greater than or equal to 0 and less than or equal to 2pi) (answered by Alan3354)

Please solve the equation: (x is less than or equal to 2pi and greater than or equal to... (answered by lwsshak3)

cos5xcos2x+sin5xsin2x= -1 for x is greater or equal to 0, and less than or equal to... (answered by Fombitz)

solve the equation for 0 less than or equal to theta less than 2pi. Write your answer as... (answered by lwsshak3)

Solve for x in the equation 3sin^2x = cos^2x; 0 (answered by stanbon)