SOLUTION: In the problem, solve the equation on the interval 0 is greater than or equal to theta is greater than 2 pie. sin theta= square root of 2 divided by 2

Question 517984: In the problem, solve the equation on the interval 0 is greater than or equal to theta is greater than 2 pie.
sin theta= square root of 2 divided by 2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve the equation on the interval 0 is <= x <= 2(pi).
sin theta= [square root of 2] divided by [2]
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sin^-1(sqrt(2)/2) = pi/4 or (3/4)pi
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Cheers,
Stan H.
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