SOLUTION: find the foci in this hyperbola equation (x+1)^2/(1)-(y-6)^2/(4)=1

Question 514603: find the foci in this hyperbola equation (x+1)^2/(1)-(y-6)^2/(4)=1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the foci in this hyperbola equation (x+1)^2/(1)-(y-6)^2/(4)=1
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(x+1)^2/(1)-(y-6)^2/(4)=1
This is an equation of a hyperbola with horizontal transverse axis of the standard form:
(x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.
For given equation: (x+1)^2/(1)-(y-6)^2/(4)=1
Center: (-1, 6)
a^2=1
b^2=4
c^2=a^2+b^2=1+4=5
c=√5
Foci=(-1�c,6)=(-1�√5,6)=(-1+√5,6) and (-1-√5,6)
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