SOLUTION: Find the remaining trigonometric ratios.
sin(θ) = 5/13, 0 < θ < π/2
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Question 505301: Find the remaining trigonometric ratios.
sin(θ) = 5/13, 0 < θ < π/2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the remaining trigonometric ratios.
sin(θ) = 5/13, 0 < θ < π/2
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Since sin = y/r, y = 5 and r = 13
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Then x = sqrt[r^2-y^2] = sqrt[169-24] = sqrt[144] = 12
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So:
sin = y/r = 5/13
cos = x/r = 12/13
tan = y/x = 4/12 = 1/3
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csc = r/y = 13/5
sec = r/x = 13/12
ctn = x/y = 12/4 = 3
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Cheers,
Stan H.
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