SOLUTION: Please help me solve this equation. it is completing the square:
2b2 + 7b + 4=0
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Question 50462: Please help me solve this equation. it is completing the square:
2b2 + 7b + 4=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2b^2 + 7b + 4=0
2(b^2+(7/2)b+? = -4
b^2+(7/2)b+(7/4)^2=-2+(7/4)^2
(b+(7/4))^2 = -32/16 + 49/16
(b+(7/4))^2 = 17/16
Take the sqrt of both sides to get:
b+7/4= (sqrt17)/4 or b+7/4 = -(sqrt17)/4
b = [-7+(sqrt17)]/4 or b = [-7-(sqrt17)]/4
Cheers,
stan H.
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