# SOLUTION: cot 60 degrees tan 210 degrees sec 210 csc 210 cot 210 cos 11pi/6 cot 3pi/2 tan 2pi/3 csc 5pi/6 please help if anyone can do it i need it by thursday 8/23/06 by 6:

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: cot 60 degrees tan 210 degrees sec 210 csc 210 cot 210 cos 11pi/6 cot 3pi/2 tan 2pi/3 csc 5pi/6 please help if anyone can do it i need it by thursday 8/23/06 by 6:      Log On

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 Question 49744: cot 60 degrees tan 210 degrees sec 210 csc 210 cot 210 cos 11pi/6 cot 3pi/2 tan 2pi/3 csc 5pi/6 please help if anyone can do it i need it by thursday 8/23/06 by 6:30 tomorrow morning please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!cot 60 degrees=1/SQRT(3) tan 210 degrees=TAN(180+30)=TAN(30)=1/SQRT(3) sec 210=SEC(180+30)=-SEC(30)=-2/SQRT(3) csc 210=COSEC(180+30)=-COSEC(30)=-2 cot 210=COT(180+30)=COT(30)=SQRT(3) cos 11pi/6=COS(2PI-PI/6)=COS(PI/6)=SQRT(3)/2 cot 3pi/2=COT(PI+PI/2)=COT(PI/2)=0 tan 2pi/3=TAN(PI-PI/3)=-TAN(PI/3)=-SQRT(3) csc 5pi/6 =COSEC(PI-PI/6)=COSEC(PI/6)=2