SOLUTION: Please help me with this problem. I need to determine if this equation might be an identity (algebraically): {{{ 1+cot^2x=(sec^2x)/(sec^2x-1) }}}

Question 494831: Please help me with this problem. I need to determine if this equation might be an identity (algebraically):
AMP Parsing Error of [ 1+cot^2x=(sec^2x)/(sec^2x-1) ]: Invalid function '\x=(sec^2\x)/(sec^2\x-1)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. .
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Please help me with this problem. I need to determine if this equation might be an identity (algebraically):
1+cot^2x=(sec^2x)/(sec^2x-1)
Starting with right side:
(1/cos^2x)/((1/cos^2x)-1)
(1/cos^2x)/((1-cos^2x)/cos^2x)
cos^2x cancel out
1/1-cos^2x
1/sin^2x
(sin^2x+cos^2x)/sin^2x
1+(cos^2x/sin^2x)=1+cot^2x
verified:
right side=left side
so equation is an identity
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