SOLUTION: solve cosx(sinx-1/2)=0 [0-2/pi]

Question 471776: solve cosx(sinx-1/2)=0 [0-2/pi]
Found 2 solutions by Tatiana_Stebko, oadeshina:
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!

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Answer by oadeshina(1) (Show Source): You can put this solution on YOUR website!
cosx*(sinx-1\2)=0
either cosx=0 or sinx-1\2=0
if sinx-1\2=0, then sinx=1\2,sinx=0.5, x=sin^1*0.5
then x=30. thanks

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