# SOLUTION: Factorise each of the following over C a) f(z)=z^3+z^2+2z-4 b)g(z)= z^3+(2-i)z^2-z-2+i i tried solving them as: a) the factor of f(z) is (z-1), then do the long division and

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: Factorise each of the following over C a) f(z)=z^3+z^2+2z-4 b)g(z)= z^3+(2-i)z^2-z-2+i i tried solving them as: a) the factor of f(z) is (z-1), then do the long division and       Log On

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 Click here to see ALL problems on Trigonometry-basics Question 470838: Factorise each of the following over C a) f(z)=z^3+z^2+2z-4 b)g(z)= z^3+(2-i)z^2-z-2+i i tried solving them as: a) the factor of f(z) is (z-1), then do the long division and the answer will be (z^2+2z+4) and so f(z)=(z-1)(z^2+2z+4) = (z-1)(z+1)^2 -1+4 <<< got stuck, how can i complete? b)the factor of g(z) is (z+2+i), then do the long division and the answer will be z^2+1 and so g(z)= (z+2-i)(z^2-1) <<<< how can i complete? ThanksAnswer by solver91311(16877)   (Show Source): You can put this solution on YOUR website! On problem number 1, so far, so good. Just like you said. Next take the quadratic factor and set it equal to zero, then solve the quadratic equation using the quadratic formula: . Hence the factors of the quadratic trinomial are: Hence: The other one is easier. Factor the quadratic factor as the difference of two squares. John My calculator said it, I believe it, that settles it