SOLUTION: (5/x)=(10/3x)+4 (assuming x≠0; note:LCD=3x) (5/x)(3x)=(10/(3x))(3x)+(4)(3x)⇛ 15=10+12x⇛ 5=12x⇛ 5/12=x How could you verify the solution? (please justif

Algebra ->  Trigonometry-basics -> SOLUTION: (5/x)=(10/3x)+4 (assuming x≠0; note:LCD=3x) (5/x)(3x)=(10/(3x))(3x)+(4)(3x)⇛ 15=10+12x⇛ 5=12x⇛ 5/12=x How could you verify the solution? (please justif      Log On


   

Question 466261: (5/x)=(10/3x)+4 (assuming x≠0; note:LCD=3x)
(5/x)(3x)=(10/(3x))(3x)+(4)(3x)⇛
15=10+12x⇛
5=12x⇛
5/12=x
How could you verify the solution? (please justify your response)
Thank you so much!
Found 2 solutions by sudhanshu_kmr, Edwin McCravy:
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

x = 5/12
to verify the solution, put the value on equation, value at left hand side will equal to value at right hand side.
L.H.S = 5/(5/12)=12
R.H.S = 10/(15/12) + 4 = 12
Verified.

Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
5%2Fx=10%2F%283x%29%2B4

To verify that x=5%2F12, substitute 5%2F12 for x in 5%2Fx=10%2F%283x%29%2B4

5%2F%285%2F12%29=10%2F%283%285%2F12%29%29%2B4

Rewrite 5%2F%285%2F12%29 as 5%22%F7%225%2F12 
Rewrite the denominator on the right 3%285%2F12%29 as 15%2F12 or 5%2F4

5%22%F7%225%2F12%22%22=%22%2210%2F%285%2F4%29%22%22%2B%22%224

Rewrite 10%2F%285%2F4%29 as 10%22%F7%225%2F4

5%22%F7%225%2F12%22%22=%22%22%22%28%2210%22%F7%225%2F4%22%29%22%22%22%2B%22%224

Invert and multiply:

5%2Aexpr%2812%2F5%29%22%22=%22%2210%2Aexpr%284%2F5%29%22%22%2B%22%224

12%22%22=%22%228%22%22%2B%22%224

12%22%22=%22%2212

Edwin