SOLUTION: Find to the nearest tenth of a degree ,all values of x in the interval 0 less than/equal to x lessthan/equal to 360 degrees that satisfy the equation 4cos^2x-5sinx-5=0 Can you p

Question 459274: Find to the nearest tenth of a degree ,all values of x in the interval 0 less than/equal to x lessthan/equal to 360 degrees that satisfy the equation 4cos^2x-5sinx-5=0
Can you please help me answer this?
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
First we simplify this equation:=>
=>=>.
In the last equation we substitute , and get the quadratic equation:
, solving this equation we get: y=-1 and y=-1/4.
Remembering our substitution we need to solve two simple
trigonometric equations equivalent with our original equation.
1), where , and
2), where , and .
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