# SOLUTION: A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Trigonometry Solvers Lessons Answers archive Quiz In Depth

 Question 456179: A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?Answer by lwsshak3(6472)   (Show Source): You can put this solution on YOUR website!A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire? .. Using quantitative analysis method: (3.5 mi/hr)*(rev/4.8π ft)*(2π rad/rev*(5280 ft/mi)*(hr/60min) all units and π cancel out except rad/min =(3.5*2*5280)/(4.8*60) rad/min =128.33 rad/min (ans) .. factors (ratios) used: rev/circumference=rev/π*diameter=rev/4.8π ft 2π rad/rev 5280 ft/mi hr/60 min