SOLUTION: A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?

Question 456179: A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?
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Using quantitative analysis method:

(3.5 mi/hr)*(rev/4.8π ft)*(2π rad/rev*(5280 ft/mi)*(hr/60min)
all units and π�cancel out except rad/min
=(3.5*2*5280)/(4.8*60) rad/min
=128.33 rad/min (ans)
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factors (ratios) used:
rev/circumference=rev/π*diameter=rev/4.8π ft
2π rad/rev
5280 ft/mi
hr/60 min
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