SOLUTION: Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x

SOLUTION: Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0

Question 455472: Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find, to the nearest degree all of the values of x.. 2 cos^2 x + 2 sin x - 1 = 0
..
2 cos^2 x + 2 sin x - 1 = 0
use following quadratic formula to solve for cos x:
..

..
a=2, b=2, c=-1
cos x=[-2�sqrt(2^2-4*2*-1)]2*2
cos x=(-2�√12)/4)
cos x=(-2�2√3)/4
cos x=-1/2�√3/2
cos x=-1/2-√3)/2=-1.366 (reject,(-1 < cos x < 1))
or
cos x=-1/2+√3)/2=.366
x=69�+2πn, 291�+2πn (n= any integer)
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