SOLUTION: I'm not sure if this is Trig, but I need help with this problem:
Beginning with cos^2X + sin^2X = 1, use algebra to develope the Pythagorean identity that involves cotX and cscX
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Question 453459: I'm not sure if this is Trig, but I need help with this problem:
Beginning with cos^2X + sin^2X = 1, use algebra to develope the Pythagorean identity that involves cotX and cscX
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Recall that 
and 
\ +\ \sin^2(x)\ =\ 1)
}\ +\ \frac{1}{\csc^2(x)}\ =\ 1)
}\ =\ 1\ -\ \frac{1}{\csc^2(x)})
Apply the LCD in the RHS:
}\ =\ \frac{\csc^2(x)\ -\ 1}{\csc^2(x)})
Multiply both sides by )
}{\sec^2(x)}\ =\ \csc^2(x)\ -\ 1)
Replace )
and )
in the LHS with their )
and )
equivalents:
}}{\frac{1}{\cos^2(x)}}\ =\ \csc^2(x)\ -\ 1)
Simplify:
}{\sin^2(x)}\ =\ \csc^2(x)\ -\ 1)
Recall that 
\ =\ \csc^2(x)\ -\ 1)
John
My calculator said it, I believe it, that settles it
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