SOLUTION: Two drivers leave home at the same time and travel on straight roads that diverge by 70 degrees. One driver travels at an average speed of 83.0 km/h. The other driver travels at an
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Question 451819: Two drivers leave home at the same time and travel on straight roads that diverge by 70 degrees. One driver travels at an average speed of 83.0 km/h. The other driver travels at an average speed of 95.0 km/h. How far apart will the two drivers be after 45 min?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two drivers leave home at the same time and travel on straight roads that diverge by 70 degrees.
One driver travels at an average speed of 83.0 km/h.
The other driver travels at an average speed of 95.0 km/h.
How far apart will the two drivers be after 45 min?
:
Convert 45 min to .75 hrs
:
Let A = 70 degrees
then
a = distance between the cars after 45 min
b = .75(83) = 62.25 km
c = .75(95) = 71.25 km
:
Use the law of cosines
a^2 = b^2 + c^2 - 2bc*cos(A)
a^2 = 62.25^2 + 71.25^2 - 2(62.25*71.25)*cos(70)
a^2 = 3875.0625 + 5076.5625 - 2(4435.3125)*.34202
a^2 = 8951.625 - 3033.9324
a =
a = 76.92 km apart after 45 min
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