SOLUTION: How do you solve cos2Θ = cosΘ where Θ, 0° ≤ Θ < 360°
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Question 445384: How do you solve cos2Θ = cosΘ where Θ, 0° ≤ Θ < 360°
Answer by poliphob3.14(115) (Show Source): You can put this solution on YOUR website!
For convenience substitute and modify the trigonometric equation:
, since and
, substituting we get: =>
=> . In the last equation
substitute and get the quadratic equation: ,
Solving this equation we find y=1 and y=-1/2.
Trigonometric equation is equivalent with two new equations:
and . Solving these equations we have;
=> degree and => , and
degree.
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