SOLUTION: Solve ∆ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree.
Thanks
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Question 44188: Solve ∆ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree.
Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve ∆ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree.
Angle A = 90-20=70 degrees
Using the Law of Sines:
a/sinA = b/SinB
a/sin70 = 10/sin20
a/0.9397=10/0.3420
a=9.397/0.3420
a=27.4767..
c=sqrt(a^2+b^2)
c=sqrt(27.47^2+10^2)
c=29.238
Cheers,
Stan H.
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