SOLUTION: Prove the identity: 1 over 1 - [(1)] over 1 - (1) over 1 - {{{(sec)^2 (x)}}} = {{{(sec)^2}}} Ok, so this question is really weird and no matter how I try , I just can't seem to

Question 438257: Prove the identity:
1 over 1 - [(1)] over 1 - (1) over 1 - AMP Parsing Error of [(sec)^2 (x)]: Invalid function ')^2(x)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. . = AMP Parsing Error of [(sec)^2]: Invalid function ')^2': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. .

Ok, so this question is really weird and no matter how I try , I just can't seem to get it right on this site. It is identity between the two sides NOT equal sign. And the part after "over" is under the one before the "over". If you can't understand, please reply back to me :(
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!

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