# SOLUTION: The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. Thank you!

Algebra ->  Algebra  -> Trigonometry-basics -> SOLUTION: The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. Thank you!       Log On

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 Click here to see ALL problems on Trigonometry-basics Question 437604: The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. Thank you! Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. ----- When the curve hits the x-axis y = 0. --- Solve: 4-3t = 0 t = (4/3) ---- Then x = 2+t^2 x = 2+(4/3)^2 x = 18/9 + 16/9 x = 34/9 ------------------------- The curve intersects at (34/9,0) ================================== Cheers, Stan H.