SOLUTION: Please help me find the eXACT solutions of the given equation, in radians, that lie in the interval [0, 2π).
6 cos3(x) + 6 cos(x) = 0
I started it by factoring
6cos(x
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Question 436796: Please help me find the eXACT solutions of the given equation, in radians, that lie in the interval [0, 2π).
6 cos3(x) + 6 cos(x) = 0
I started it by factoring
6cos(x)*[cos2(x)+cos(x)]=0
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
==> cos3x + cosx = 0
==> cos2x cosx - sin2x sinx + cosx = 0
==>
==>
==>
==>
==>
==> cosx = 0 ==> x = , ;
==> Also, , or ,
==> x = , , , .
==> Solution set is { , , , , , }.
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