SOLUTION: prove the idenity true sec^4x-(tan^4x+sec^2x)=sec^2x*sin^2x

Algebra.Com
Question 433747: prove the idenity true
sec^4x-(tan^4x+sec^2x)=sec^2x*sin^2x

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
prove the idenity true
sec^4x-(tan^4x+sec^2x)=sec^2x*sin^2x
starting with left side
sec^4x-(tan^4x+sec^2x)
1/cos^4-sin^4/cos^4-1/cos^2
LCD:cos^4
(1-sin^4-cos^2)/cos^4
(sin^2-sin^4)/cos^4
sin^2(1-sin^2)/cos^4
sin^2*cos^2/cos^4
sin^2/cos^2
sin^2*sec^2
left side=right side

RELATED QUESTIONS

verify the idenity sec^4x – sec^2x = tan^4x +... (answered by Edwin McCravy)
verify identinty sec^4x – (tan^4x + sec^2x) = sec^2x · sin^2x (answered by Alan3354)
sec^4x – sec^2x = tan^4x +... (answered by Alan3354)
verify the idenity sec^2x – csc^2x = (tan x – cot x)/(sinx*cosx) (answered by Alan3354)
verify the idenity sec^2x – csc^2x = (tan x – cot... (answered by Edwin McCravy)
Show that tan^2x - sin^2x=sin^4x(sec^2x) Where x is an... (answered by Alan3354)
Prove: (sec^2x -1) / (sec^2x)= sin^2x Thanks (answered by lwsshak3)
please help me prove this equation:... (answered by vicgonzerx)
Show that... (answered by MathLover1)