The approach pattern to an airport requires pilots to set an 11o angle of descent toward a runway. If a plane is flying at an altitude of 9,500 m, at what distance (measured along the ground) from the airport must the pilot decend P · · | 9500 m A · 11° | ·--------------------------------- x B The plane is at P, the Airport is at A, B is a point on the ground directly under the plane. We want to find AB, the length of which we call x 9500 is the opposite side to 11° x is the adjacent side to 11° tan(11°) = opposite/adjacent tan(11°) = 9500/x x·tan(11°) = 9500 x = 9500/tan(11°) x = 48873.26315 m or about 48900 meters. Edwin AnlytcPhil@aol.com