SOLUTION: Find the solution of sin 2 θ = cos θ if 0° < or = 180°.
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Question 42532
:
Find the solution of sin 2 θ = cos θ if 0° < or = 180°.
Answer by
fractalier(2101)
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Let q be the theta because I can't write theta...so
sin 2q = cos q
2 sin q cos q = cos q
2 sin q = 1
sin q = 1/2
q = 30 or 150 degrees = (pi)/6 or 5(pi)/6 radians
Both solutions check too.