SOLUTION: can you help me solve this fundamental identities....please.. 1.) cosēθ(tanē θ+1)=1 2.) secē θcotē=1+cotē θ 3.)Sin θ__ =cscθ-cot θ 1+c

Algebra.Com
Question 421850: can you help me solve this fundamental identities....please..
1.) cosēθ(tanē θ+1)=1
2.) secē θcotē=1+cotē θ
3.)Sin θ__ =cscθ-cot θ
1+cos θ
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

cosēθ(tanēθ+1)=1         | (tanēθ+1)= secθē = 1/cosēθ 

cosēθ/cosēθ = 1

            1 = 1



 secēθ cotē=1+cotēθ 

 secēθcotē- cotēθ = 1

 cotēθ(secēθ - 1) = 1    | secēθ - 1 = tanēθ

 cotēθtanēθ  = 1         | tanēθ = 1/cotēθ 

 cotēθ/cotēθ = 1

           1 = 1



Sinθ/(1+cos θ) = cscθ-cot θ   |cscθ = 1/sinθ and cotθ = cosθ/sinθ

Sinθ/(1+cos θ) = (1-cosθ)/sinθ

sinēθ  = (1+cos θ)(1-cos θ)

 sinēθ = 1 - cosēθ

  sinēθ + cosēθ = 1      |pythagorean Identity 

RELATED QUESTIONS


Please help me solve this question:

Prove the following identities

a. sin {θ}... (answered by tommyt3rd)

prove 
(1 / tan^2θ ) + (1 / 1+ cot^2θ) = 1
and
(sinθ +... (answered by chibisan)

Verify The Following Identities: 

1.cotα + tanα = cscα secα... (answered by stanbon)

Can you please help me with this problem?
Cosθ (tan θ+cot θ)=csc θ   (answered by lwsshak3)

verify an identity:
1) tan(t)+ 2 cos(t)csc(t)=sec(t)+csc(t)+cot(t)... (answered by solver91311)

The expression sin θ(cotθ - cscθ) is equivalent to
1) cotθ -... (answered by stanbon)

Let csc θ = 19/6 , 0 < θ < pi/2

sinθ= 6/19 Find: cosθ, tanθ,... (answered by lwsshak3)

Can you prove each identity? And can you show me the solution so that I can do it next... (answered by lwsshak3)

Instructions: Transform the left side of the equation into the right side using... (answered by stanbon)