# SOLUTION: write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2)

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 Question 414998: write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2)Answer by lwsshak3(6463)   (Show Source): You can put this solution on YOUR website!write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2) .. Standard form of the parabola: y=A(x-h)^2+k, with (h,k)= (x,y) coordinates of vertex, and A = coefficient of (x-h)^2. The problem in given case is to find A. given parabola: y=A(x+3)^2+6 using given point (1,-2),solve for A -2=A(1+3)^2+6 -2=A(4^2)+6 -8=16A A=-1/2 Equation of parabola: y=-1/2(x+3)^2+6 The graph below is what the parabola looks like. ..