SOLUTION: sinx*cos^2x=sinx

Question 413725: sinx*cos^2x=sinx
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
sin(x)*cos²(x) = sin(x)
We'll start by subtracting sin(x) from each side:
sin(x)*cos²(x) - sin(x) = 0
And then factor out sin(x):
sin(x)*(cos²(x) - 1) = 0
The expression inside the parentheses is not 1 - cos²(x) but it is the negative of 1 - cos²(x). So the expression inside the parentheses is -1 -sin²(x):
sin(x)(-sin²(x)) = 0
or
-sin³(x) = 0

So the solution will be all x values whose sin is zero. If you know your special values then you know that sin is zero for 0 and radians or any of the angles coterminal with these. So:
x = 0 + 2n
or
x = + 2n
where "n" is any integer. (The "n" is the way we use to include the angle coterminal with 0 and radians.)

Note: If you don't know what a radian is and/or if you wanted an answer in degrees, then change the to 180 and the 2 to 360.
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