Hi

Determine the sum and product of the roots of  

3y^2– 2y + 12 = 0









Roots are {1/3 + isqrt(35), 1/3 -isqrt(35)/3}

Sum of roots is 2/3

Product of roots is [1/3 + isqrt(35)][1/3 - isqrt(35)] = 1/9 + 35 = 35 1/9

                       Note i^2 = -1  

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
 





Use the quadratic formula to calculate the two complex roots of the equation.  Then multiply the two roots.  They are complex conjugates, so the result is the SUM of two squares (not the difference because ).





The sum of the two roots is simply two times the real part because the imaginary parts are of opposite signs.







John



My calculator said it, I believe it, that settles it



 

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